Can you divide dictionaries in python?

The elements in tow lists can be involved in a division operation for some data manipulation activity using python. In this article we will see how this can be achieved.

With zip

The zip function can pair up the two given lists element wise. The we apply the division mathematical operator to each pair of these elements. Storing the result into a new list.

Example

 Live Demo

# Given lists
list1 = [12,4,0,24]
list2 = [6,3,8,-3]

# Given lists
print("Given list 1 : " + str(list1))
print("Given list 2 : " + str(list2))

# Use zip
res = [i / j for i, j in zip(list1, list2)]

print(res)

Output

Running the above code gives us the following result −

Given list 1 : [12, 4, 0, 24]
Given list 2 : [6, 3, 8, -3]
[2.0, 1.3333333333333333, 0.0, -8.0]

With truediv and map

The truediv operator is a part of python standard library called operator. It performs the true division between the numbers. We also use the map function to apply the division operator iteratively for each pair of elements in the list.

Example

 Live Demo

from operator import truediv
# Given lists
list1 = [12,4,0,24]
list2 = [6,3,8,-3]

# Given lists
print("Given list 1 : " + str(list1))
print("Given list 2 : " + str(list2))

# Use zip
res = list(map(truediv, list1, list2))

print(res)

Output

Running the above code gives us the following result −

Given list 1 : [12, 4, 0, 24]
Given list 2 : [6, 3, 8, -3]
[2.0, 1.3333333333333333, 0.0, -8.0]

Updated on 05-May-2020 10:06:59

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Dividing values of dictionaries by values of another dictionary python

Questions : Dividing values of dictionaries by values of another dictionary python

2022-09-17T19:38:58+00:00 2022-09-17T19:38:58+00:00

823

I have a dictionary, dict1, in the following anycodings_division format:

{0: 301, 1: 410, 2: 289}

I have another dictionary, dict2:

{0: 5307, 2: 4925}

I would like to divide the value of dict2 by anycodings_division the value of dict1, based on the keys. For anycodings_division example 5307 would be divided by 301 since anycodings_division their keys are both 0. Any suggestions?

Total Answers 3

32

Answers 1 : of Dividing values of dictionaries by values of another dictionary python

>>> d1 = {0: 301, 1: 410, 2: 289}
>>> d2 = {0: 5307, 2: 4925}
>>> {k: d2[k] / float(d1[k]) for k in d1 if k in d2}
{0: 17.631229235880397, 2: 17.041522491349482}

If your Python (eg 2.6) is too old for anycodings_division dict comprehensions, you can use

>>> dict((k, d2[k] / float(d1[k])) for k in d1 if k in d2)
{0: 17.631229235880397, 2: 17.041522491349482}

If your Python is even older than 2.6

>>> dict([(k, d2[k] / float(d1[k])) for k in d1 if k in d2])
{0: 17.631229235880397, 2: 17.041522491349482}

In Python3, you don't need the float anycodings_division call

>>> {k: d2[k] / d1[k] for k in d1 if k in d2}
{0: 17.631229235880397, 2: 17.041522491349482}

0

2022-09-17T19:38:58+00:00 2022-09-17T19:38:58+00:00Answer Link

mRahman

2

Answers 2 : of Dividing values of dictionaries by values of another dictionary python

def divide(dividends, divisors):
    ret = dict()
    for key, dividend in dividends.items():
        ret[key] = dividend/divisors.get(key, 1)
    return ret

0

2022-09-17T19:38:58+00:00 2022-09-17T19:38:58+00:00Answer Link

joy

4

Answers 3 : of Dividing values of dictionaries by values of another dictionary python

Loop over every item the length of the anycodings_division smallest dict. Then add the values to anycodings_division another dict, values.

>>> dict1 = {0: 301, 1: 410, 2: 289}
>>> 
>>> dict2 = {0: 5307, 1: 4925}
>>> 
>>> length = {len(dict1): 'dict1', len(dict2): 'dict2'}
>>> small = min(length)
>>> values = {}
>>> 
>>> for k in range(small):
...     values[k] = dict1[k]*dict2[k]
... 
>>> print values
{0: 1597407, 1: 2019250}
>>> 

0

2022-09-17T19:38:58+00:00 2022-09-17T19:38:58+00:00Answer Link

jidam

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